The set of values of p for which the roots of the equation 3x2+2x+p (p−1)=0 are of opposite signs is
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a
(−∞,0)
b
(0,1)
c
(1,∞)
d
(0,∞)
answer is B.
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Detailed Solution
The given equation is 3x2+2x+p (p−1)=0 The Roots of given equation are of opposite signs ⇒ Product of roots <0 ⇒ constant term coeff. of x2<0 ⇒ p(p−1)3 <0 ⇒ (P−0) (P−1) <0 ⇒ 0