The set of values of ‘a’ for which the equation cos2x+asinx=2a−7 possesses a solution is c,d, then c+d=
2
4
6
8
We have cos2x+asinx=2a−7
⇒1−2sin2x+asinx=2a−7
⇒2sin2x−asinx+2a−8=0
⇒sinx=a±a2−8(2a−8)4=a±(a−8)24
⇒sinx=a±(a−8)4=2a−84 or 2
Now −1≤sinx≤1⇒−1≤2a−84≤1
⇒−4≤2a−8≤4⇒4≤2a≤12⇒2≤a≤6
∴c=2,d=6⇒c+d=8