Set of values of a for which the function f:R→R is given by f(x)=x3+(a+2)x2+3ax+10 is one-one, is given by
(−∞,1]∪[4,∞)
(1,4)
[1,∞)
(−∞,4)
f:R→R; f(x)=x3+(a+2)x2+3ax+10 is one-one.
Equational process in this is difficult, we use the fact that f(x) is one-one in R , then it must be either increasing in R or decreasing in R
∴ f'(x)=3x2+2(a+2)x+3a>0 ∀ x∈R
<0∀x∈R
As coefficient of x2=3>0 , f'(x) cannot be negative for all x∈R
3x2+2(a+2)x+3a>0∀x∈R
⇒ 4(a+2)2−36a<0
⇒ a2−5a+4<0 i.e., (a−1)(a−4)<0
⇒ 1<a<4 i.e., a∈(1,4) .