Download the app

Questions  

The set of values of 'a' for which the point (a1,a+1) lies outside the circle X2+Y2=8 and inside the circle x2+y212x+12y62=0, is

a
(−∞,−3)∪(3,∞)
b
(−32, 32)
c
(−32,−3)∪(3,32)
d
none of these

detailed solution

Correct option is C

It is given that the point (a−1,a+1) lies outside the circle x2+y2=8 and inside the circle x2+y2−12x+12y−62=0. Therefore,     (a−1)2+(a+1)2−8>0and, (a−1)2+(a+1)2−12(a−1)+12(a+1)−62<0⇒ 2a2−6>0 and 2a2−36<0⇒ a2−3>0 and a2−18<0⇒ a∈(−∞,−3)∪(3,∞) and a∈(−32,32)⇒ a∈(−32,−3)∪(3,32)

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The set of values of a for which the point (2a, a+1) is an interior point of the larger segment of the circle x2+y2-2x-2y-8=0made by the chord x-y+1=0,is 


phone icon
whats app icon