The set of values of 'a' for which the point (a−1,a+1) lies outside the circle X2+Y2=8 and inside the circle x2+y2−12x+12y−62=0, is

It is given that the point (a−1,a+1) lies outside the circle x2+y2=8 and inside the circle x2+y2−12x+12y−62=0. Therefore,     (a−1)2+(a+1)2−8>0and, (a−1)2+(a+1)2−12(a−1)+12(a+1)−62<0⇒ 2a2−6>0 and 2a2−36<0⇒ a2−3>0 and a2−18<0⇒ a∈(−∞,−3)∪(3,∞) and a∈(−32,32)⇒ a∈(−32,−3)∪(3,32)