The set of values of x satisfying the inequation tan2⁡sin−1⁡x>1, is

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[−1, 1]

−12, 12

(−1, 1)−−12, 12

[−1, 1]−−12, 12

answer is C.

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Detailed Solution

We have,tan2⁡sin−1⁡x>1⇒tan2⁡sin−1⁡x−1>0⇒ tan⁡sin−1⁡x<−1 or, tan⁡sin−1⁡x>1⇒ −∞