Q.
The set of values of x satisfying the inequation tan2sin−1x>1, is
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a
[−1, 1]
b
−12, 12
c
(−1, 1)−−12, 12
d
[−1, 1]−−12, 12
answer is C.
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Detailed Solution
We have,tan2sin−1x>1⇒tan2sin−1x−1>0⇒ tansin−1x<−1 or, tansin−1x>1⇒ −∞
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