The set of values of x satisfying the inequation tan2sin−1x>1, is
[−1, 1]
−12, 12
(−1, 1)−−12, 12
[−1, 1]−−12, 12
We have,
tan2sin−1x>1⇒tan2sin−1x−1>0⇒ tansin−1x<−1 or, tansin−1x>1⇒ −∞<tansin−1x<−1 or, 1<tansin−1x<∞⇒ −π2<sin−1x<−π4 or, π4<sin−1x<π2⇒ x∈−1,−12 or, x∈12,1⇒ x∈(−1,−1)−−12,12