The set of values of x for which tan−1x1−x2=sin−1x holds,
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a
R
b
(-1, 1)
c
[0, 1]
d
[-1, 0]
answer is B.
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Detailed Solution
We observe that RHS is defined for all x∈[−1, 1]whereas LHS is meaningful for -1 < x < l.Also, for x∈(−1, 1), we havetan−1x1−x2=tan−1sinθcosθ, where x=sinθ=θ=sin−1x