Questions
Seven persons sit in a row at random. The probability that three persons A, B, C sit together in a particular order is
detailed solution
Correct option is C
The number of ways of arrainging 7 boys among themselves is n(S)=7! Let E be the event of having three persons A,B,C are together in a perticular order Take A,B,C as one bunch, the number of ways of arranging 5 things in 5! waysn(E)=5! Therefore, the probability is P(E) =5!7!Talk to our academic expert!
Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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