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Q.

The shortest distance between the lines r=(4i−j)+λ(i+2j−3k) and r=(i−j+2k)+μ(2i+4j−5k) is

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a

6

b

5

c

6/5

d

65

answer is C.

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Detailed Solution

d=[(4i−j)−(i−j+2k)]⋅(i+2j−3k)×(2i+4j−5k)|(i+2j−3k)×(2i+4j−5k)|=(3i−2k)⋅(2i−j)|2i−j|=65.

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