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The shortest distance between the lines
$\frac{x - 3}{3} = \frac{y - 8}{- 1} = \frac{z - 3}{1} and \frac{x + 3}{- 3} = \frac{y + 7}{2} = \frac{z - 6}{4} is:$

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Correct option is D

AB→=6i^+15j^+3k^p¯=i^+4j^+22k^q¯=i^+j^+7k^p¯×q¯=ijk1422117=6i^+15j^-3k^ S.D =|AB·(p¯×q¯)||p¯×q→|=|36+225+9|36+225+9=330

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The shortest distance between the linesx-33=y-8-1=z-31 and x+3-3=y+72=z-64 is:

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The shortest distance between the lines
$\frac{x - 3}{3} = \frac{y - 8}{- 1} = \frac{z - 3}{1} and \frac{x + 3}{- 3} = \frac{y + 7}{2} = \frac{z - 6}{4} is:$