The shortest distance from the plane 12x+4y+3z=327 to the sphere x2+y2+z2+4x−2y−6z=155 is
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a
39
b
26
c
11413
d
13
answer is D.
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Detailed Solution
Shortest distance =perpendicular distance between the plane and sphere =distance of plane from centre of sphere –radius =|−2×12+4×1+3×3−327144+9+16|−4+1+9+155 =26−13=13