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Q.

The side of a cube increases at the rate of 0.01 cm/sec. The rate of increase in the surface area of the cube when the side is 4cm is

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a

0.38 sq. cm/sec .

b

0.48 sq. cm/sec .

c

10 sq. cm/sec .

d

15 sq. cm/sec .

answer is B.

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Detailed Solution

dxdt=0.01         s=6x2,  x=4         dsdt=12x.dxdt         = 12×4×(0.01)         = 0.48sq.cm/sec
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