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${The sides of a triangle ABC satisfy the relations a+b-c=2 and 2ab-c}^{2} = 4 . t hen square of the area of triangle is$

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Correct option is C

a+b-c=2----1and 2ab-c2=4-----2⇒a2+b2+c2+2ab-2bc-2ca=4=2ab-c2⇒b-c2+a-c2=0⇒a=b=ctriangle is equilateral⇒a=2⇒∆=3

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The sides of a triangle ABC satisfy the relations a+b-c=2 and 2ab-c2=4. then square of the area of triangle is

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${The sides of a triangle ABC satisfy the relations a+b-c=2 and 2ab-c}^{2} = 4 . t hen square of the area of triangle is$