The sides of a triangle ABC satisfy the equation 2a2+4b2+c2=4ab+2ac. Then

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Triangle is isosceles

triangle is obtuse

∠B=cos−1⁡78

∠A=cos−1⁡14

answer is A.

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Detailed Solution

The sides of a. a2−2ac+c2+(2b)2+a2−4ab=0(a−c)2+(a−2b)2=0a=c;a=2bΔ is isosceles therefore cos⁡B=a2+c2−b22ac=78cos⁡A=b2+c2−a22ac=14

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