The simplified form of tan−13a2x−x3a3−3ax2, a>0;−a3≤x≤a3 is
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a
3tan−1xa
b
2tan−1xa
c
3tan−1ax
d
None of these
answer is A.
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Detailed Solution
Let x = a tan θ⇒ xa=tanθ⇒ θ=tan−1xa∴tan−13a2x−x3a3−3ax2=tan−13a2(atanθ)−(atanθ)3a3−3a(atanθ)2 =tan−1a33tanθ−tan3θa31−3tan2θ=tan−13tanθ−tan3θ1−3tan2θ=tan−1(tan3θ)=3θ=3tan−1xa [from Eq. (i)]