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Questions  

The simplified form of tan13a2xx3a33ax2, a>0;a3xa3 is 

a
3tan−1⁡xa
b
2tan−1⁡xa
c
3tan−1⁡ax
d
None of these

detailed solution

Correct option is A

Let x = a tan θ⇒    xa=tan⁡θ⇒   θ=tan−1⁡xa∴tan−1⁡3a2x−x3a3−3ax2=tan−1⁡3a2(atan⁡θ)−(atan⁡θ)3a3−3a(atan⁡θ)2 =tan−1⁡a33tan⁡θ−tan3⁡θa31−3tan2⁡θ=tan−1⁡3tan⁡θ−tan3⁡θ1−3tan2⁡θ=tan−1⁡(tan⁡3θ)=3θ=3tan−1⁡xa     [from Eq. (i)]

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