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$\frac{\sin (B - C)}{\cos B \cos C} + \frac{\sin (C - A)}{\cos C \cos A} + \frac{\sin (A - B)}{\cos A \cos B} = λ$ then $λ =$

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Correct option is A

First term=sinBcosC−cosBsinCcosBcosC=tanB−tanC∴∑sinB−CcosBcosC=tanB−tanC+tanC−tanA+tanA−tanB=0

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sinB−CcosBcosC+sinC−AcosCcosA+sinA−BcosAcosB=λthen λ=

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$\frac{\sin (B - C)}{\cos B \cos C} + \frac{\sin (C - A)}{\cos C \cos A} + \frac{\sin (A - B)}{\cos A \cos B} = λ$ then $λ =$