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a
θ∈0,π2
b
θ∈π2,π
c
θ∈π,3π2
d
θ∈3π2,2π
answer is B.
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Detailed Solution
sin2θ+cos2θ+sinθcosθ−cosθ|cosecθ|−2=−1or 1+sinθcosθ−|sinθ|cosθ−1=0or cosθ(sinθ−|sinθ|)=0⇒θ∈0,π2 or θ∈π2,π But θ≠π4 (not in domain); therefore, θ∈π2,π