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$\frac{2 + \sin^{6} θ + \cos^{6} θ}{\sin^{2} θ + \cos^{4} θ} =$

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detailed solution

Correct option is C

2+sin6θ+cos6θsin2θ+cos4θ=2+sin2θ+cos2θ3-3sin2θcos2θsin2θ+cos2θsin2θ+cos2θ1-sin2θ =2+1−3sin2θcos2θ1−sin2cos2θ =31−sin2θcos2θ1−sin2cos2θ =3

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