sin–1 [cos (sin–1x)] + cos–1 [sin (cos–1x)] is equal to
π4
π2
3π4
0
We havesin–1cos (sin–1x)) + cos–1(sin (cos–1x))=sin−1cosπ2−cos−1x+cos−1sinπ2−sin−1x=sin−1sincos−1x+cos−1cossin−1x=cos−1x+sin−1x=π2