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sin^–1 [cos (sin^–1x)] + cos^–1 [sin (cos^–1x)] is equal to

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Correct option is B

We havesin–1cos (sin–1x)) + cos–1(sin (cos–1x))=sin−1⁡cos⁡π2−cos−1⁡x+cos−1⁡sin⁡π2−sin−1⁡x=sin−1⁡sin⁡cos−1⁡x+cos−1⁡cos⁡sin−1⁡x=cos−1⁡x+sin−1⁡x=π2

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sin–1 [cos (sin–1x)] + cos–1 [sin (cos–1x)] is equal to

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sin^–1 [cos (sin^–1x)] + cos^–1 [sin (cos^–1x)] is equal to