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$\frac{4 \sin 7^{o} \sin 67^{o} \sin 53^{o}}{\sin 21^{o}} =$

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detailed solution

Correct option is A

We have sinθ·sin60°+θsin60°-θ=14sin3θ∴sin7°sin67°sin53°=14sin21°⇒4sin7°sin67°sin53°sin21°=1

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4sin7osin67osin53osin21o=

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$\frac{4 \sin 7^{o} \sin 67^{o} \sin 53^{o}}{\sin 21^{o}} =$