Q.
sin23π24=2p−q−14rthen the value of p2−q2−r2=
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a
3
b
6
c
4
d
9
answer is D.
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Detailed Solution
sin23π24=sinπ-π24 =sinπ24We have 2sin2π24=1-cosπ12 =1-cos15°∴sin2π24=1-3+1222⇒sinπ24=22-3-142⇒p=2,q=3 and r=2⇒p2+q2-r2=9
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