Q.

sin23π24=2p−q−14rthen the value of p2−q2−r2=

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a

3

b

6

c

4

d

9

answer is D.

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Detailed Solution

sin23π24=sinπ-π24                   =sinπ24We have 2sin2π24=1-cosπ12                                 =1-cos15°∴sin2π24=1-3+1222⇒sinπ24=22-3-142⇒p=2,q=3 and r=2⇒p2+q2-r2=9
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