$$sin2$$⁡π$$8+A2$$−$$sin2$$⁡π$$8$$−$$A2$$ is equal to

Correct option is 1(1/2)sin⁡A

Questions

$\sin^{2} (\frac{π}{8} + \frac{A}{2}) - \sin^{2} (\frac{π}{8} - \frac{A}{2})$ is equal to

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(1/2)sin⁡A

(1/2)cos⁡A

2sin⁡A

2cos⁡A

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detailed solution

Correct option is A

Use :sin2⁡A−sin2⁡B=sin⁡(A−B)sin⁡(A+B)

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sin2⁡π8+A2−sin2⁡π8−A2 is equal to

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$\sin^{2} (\frac{π}{8} + \frac{A}{2}) - \sin^{2} (\frac{π}{8} - \frac{A}{2})$ is equal to