${\left(\frac{\sin {33}^{\circ }}{\sin {11}^{\circ }\sin {49}^{\circ }\sin {71}^{\circ }}\right)}^2+{\left(\frac{\cos {33}^{\circ }}{\cos {11}^{\circ }\cos {49}^{\circ }\cos {71}^{\circ }}\right)}^2$ is equal to _______.

Given expression is ${\left(\frac{\sin {33}^{\circ }}{\sin {11}^{\circ }\sin \left({60}^{\circ }-{11}^{\circ }\right)\sin \left(60+{11}^{\circ }\right)}\right)}^2+{\left(\frac{\cos {33}^{\circ }}{\cos {11}^{\circ }\cos \left({60}^{\circ }-{11}^{\circ }\right)\cos \left({60}^{\circ }+{11}^{\circ }\right)}\right)}^2$

                               $$\begin{gathered} ={\left(\frac{\sin {33}^{\circ }}{\frac{1}{4}\sin {33}^{\circ }}\right)}^2+{\left(\frac{\cos {33}^{\circ }}{\frac{1}{4}\cos {33}^{\circ }}\right)}^2 \\ =16+16=32 \end{gathered}$$