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Q.

sin⁡3θ+sin⁡5θ+sin⁡7θ+sin⁡9θcos⁡3θ+cos⁡5θ+cos⁡7θ+cos⁡9θ is equal to

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a

tan⁡ 3θ

b

cot⁡ 3θ

c

tan⁡ 6θ

d

cot⁡ 6θ

answer is C.

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Detailed Solution

sin⁡ 3θ+sin⁡ 5θ+sin⁡ 7θ+sin⁡ 9θcos⁡ 3θ+cos⁡ 5θ+cos⁡ 7θ+cos⁡ 9θ            =(sin⁡ 3θ+sin⁡ 9θ)+(sin⁡ 5θ+sin⁡ 7θ)(cos⁡ 3θ+cos⁡ 9θ)+(cos⁡ 5θ+cos⁡ 7θ)=2sin⁡ 6θ cos⁡ 3θ+2sin⁡ 6θ cos⁡ θ2cos⁡ 6θ cos⁡ 3θ+2cos⁡ 6θ cos⁡ θ=2sin⁡ 6θ(cos⁡ 3θ+cos⁡ θ)2cos⁡ 6θ(cos⁡ 3θ+cos⁡ θ)=tan⁡ 6θ
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