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Q.

sin⁡47∘+sin⁡61∘−sin⁡11∘−sin⁡25∘ is equal to

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a

sin⁡7∘

b

cos⁡7∘

c

sin⁡36∘

d

cos⁡36∘

answer is B.

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Detailed Solution

sin⁡47∘−sin⁡25∘+sin⁡61∘−sin⁡11∘=2cos⁡36∘sin⁡11∘+2cos⁡36∘sin⁡25∘=2cos⁡36∘sin⁡11∘+sin⁡25∘=2cos⁡36∘2sin⁡25∘+11∘2cos⁡25∘−11∘2=45+145−14cos⁡7∘=5−14cos⁡7∘=cos⁡7∘
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