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$\sin 47^{\circ} + \sin 61^{\circ} - \sin 11^{\circ} - \sin 25^{\circ}$ is equal to

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sin⁡7∘

cos⁡7∘

sin⁡36∘

cos⁡36∘

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detailed solution

Correct option is B

sin⁡47∘−sin⁡25∘+sin⁡61∘−sin⁡11∘=2cos⁡36∘sin⁡11∘+2cos⁡36∘sin⁡25∘=2cos⁡36∘sin⁡11∘+sin⁡25∘=2cos⁡36∘2sin⁡25∘+11∘2cos⁡25∘−11∘2=45+145−14cos⁡7∘=5−14cos⁡7∘=cos⁡7∘

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sin⁡47∘+sin⁡61∘−sin⁡11∘−sin⁡25∘ is equal to

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$\sin 47^{\circ} + \sin 61^{\circ} - \sin 11^{\circ} - \sin 25^{\circ}$ is equal to