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Q.

sin−1(sin10)+sin−1(sin12)+cos−1−12=

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a

2−π3

b

22+2π3

c

2+π3

d

2-π3

answer is A.

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Detailed Solution

sin-1(sin10)=3π-10sin-1(sin12)=12-4π∴GE=3π-10+12-4π+2π3=2-π3
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