First slide

Introduction to ITF

Question

$\sin^{- 1} (\sin 10) + \sin^{- 1} (\sin 12) + \cos^{- 1} (\frac{- 1}{2}) =$

Easy

A

$2 - \frac{π}{3}$
B

$22 + \frac{2 π}{3}$
C

$2 + \frac{π}{3}$
D

$2 - \frac{π}{3}$

Solution

$\sin^{- 1} (\sin 10) = 3 π - 10$
$\sin^{- 1} (\sin 12) = 12 - 4 π$
$∴ G E = 3 π - 10 + 12 - 4 π + \frac{2 π}{3} = 2 - \frac{π}{3}$

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