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$\frac{\sin 1^{0} + \sin 2^{0} + \sin 3^{0} + \sin 4^{0}}{\cos 1^{0} + \cos 2^{0} + \cos 3^{0} + \cos 4^{0}} =$

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Correct option is A

We have sinα+sinα+d+.....sinα+n−1dcosα+cosα+d+.....cosα+n−1d=sinα+α+n−1d2cosα+α+n−1d2∴sin1∘+sin2∘+sin3∘+sin4∘cos1∘+cos2∘+cos3∘+cos4∘=sin1+42ocos1+42o=tan52o

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sin10+sin20+sin30+sin40cos10+cos20+cos30+cos40=

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$\frac{\sin 1^{0} + \sin 2^{0} + \sin 3^{0} + \sin 4^{0}}{\cos 1^{0} + \cos 2^{0} + \cos 3^{0} + \cos 4^{0}} =$