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Q.

a=1+sinx1−cosx+sinx⇒1+cosx+sinx2sinx=

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a

2a

b

3a

c

4a

d

a

answer is D.

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Detailed Solution

1+cosx+sinx2sinx=1+cosx+sinx1-cosx+sinx2sinx1-cosx+sinx        (multiply and divide by (1+cosx+sinx))                           =1+sinx2-cos2x2sinx1-cosx+sinx =2sinx1+sinx2sinx1-cosx+sinx =1+sinx1-cosx+sinx =a
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a=1+sinx1−cosx+sinx⇒1+cosx+sinx2sinx=