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Q.

sinx+sin2x+sin3x=1⇒cos6x−4cos4x+8cos2x=

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a

4

b

0

c

1

d

2

answer is A.

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Detailed Solution

sinx(1+sin2x)=cos2xSquaring both sides we get (1−cos2x)(2−cos2x)2=cos4x 1-cos2x4+cos4x-4cos2x=cos4xSimplify further
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