First slide

Theorems of probability

Question

Six dice are thrown. The probability that different numbers will turn up is:

Very Easy

A

_{$\frac{129}{1296}$}
B

_{$\frac{1}{54}$}
C

_{$\frac{5}{324}$}
D

_{$\frac{5}{54}$}

Solution

The number of ways of getting the different numbers 1, 2, ……….., 6 in six dice = 6!
Total number of ways = _$6^{6}$

Hence, required probability=_{$= \frac{6!}{6^{6}} = \frac{1 \times 2 \times 3 \times 4 \times 5 \times 6}{6^{6}} = \frac{5}{324}$}

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