Questions
can be seated, is:
detailed solution
Correct option is B
Consider AB as one unit. C and D are to be separated; E and F any where AB and E, F can be seated in a row in 3! x 2! ways No. of gaps between AB, E, F is 4 □ AB □ E □ F □ In those 4 gaps C,D can be seated in C2 4 x 2! ways Total number of ways = 3! x2! x C2 4x 2!=144Similar Questions
Let be a set containing elements. The number of reflexive relations that can be defined on is
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