Slope of a line passing through P (2,3) and intersecting the line, x+y=7 at a distance of 4 units from P, is

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1−51+5

1−71+7

7−17+1

5−15+1

answer is B.

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Detailed Solution

d = distance from point (2,3) to x+y-7=0d=2 from ΔPQR PR2+RQ2=PQ2d2+RQ2=4222+RQ2=16RQ=14⇒tanθ=dQR=17|m+11−m|=17⇒m=1−71+7 or 1+71−7

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