Questions
The slope of the line touching both the parabolas
and is
detailed solution
Correct option is A
Equation of the tangent at t2,2t to the parabola y2=4x is ty=x+t2 (1)and the tangent at t−16t′,−8t2 to the parabola x2=−32yt′x=y−8t′2 (2)Since (1) and (2) represent the same line, comparing we get 1−t′=−t1=t2−8t′2⇒t=2Hence the required slope of the tangent is 1t=12.Talk to our academic expert!
Similar Questions
The length of the perpendiculars from the focus
and the extremities of a focal chord of a parabola
on the tangent at the vertex form
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