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$Slope of normal to a curve y = f (x) at any point on curve is \frac{x}{y} and curve is passing$
$through the point (1, 1) . Then area formed by y = f (x), x - axis x = 3 and x = 5 is$

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detailed solution

Correct option is B

−dxdy=xy⇒ydx+xdy=0d(xy)=0xy=c(1,1)⇒xy=1 Area =∫35 1xdx=[log⁡x]35=log⁡5−log⁡3=log⁡(5/3)

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Slope of normal to a curve y=f(x) at any point on curve is xy and curve is passing through the point (1,1) . Then area formed by y=f(x),x - axis x=3 and x=5 is

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

$Slope of normal to a curve y = f (x) at any point on curve is \frac{x}{y} and curve is passing$
$through the point (1, 1) . Then area formed by y = f (x), x - axis x = 3 and x = 5 is$