Slope of normal to a curve y=f(x) at any point on curve is xy and curve is passing
through the point (1,1) . Then area formed by y=f(x),x - axis x=3 and x=5 is
53
log53
log15
1
−dxdy=xy⇒ydx+xdy=0d(xy)=0xy=c(1,1)⇒xy=1 Area =∫35 1xdx=[logx]35=log5−log3=log(5/3)