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Q.

The slope of the normal at (−2, 0) on the curve y=x2+3x−2 is

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a

1

b

−1

c

12

d

−12

answer is A.

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Detailed Solution

y=x2+3x−2  P(−2,0) m=(dydx)(−2,0)=2x+3=−1 Slope of normal =−1m=1
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