The slope of a straight line passing through A(–2,3) is –43 . The points on the line that are 10 unit away from A are
(– 8,11),(4,– 5)
(–7,9), (17,–1)
(7, 5),(– 1,–1)
None of these
The given point is A(-2,3) and the slope of the line is -43 The points on the line that are at ' r' units from A are -2±rcosθ,3±rsinθ Here tanθ=-43⇒sinθ=45 and cosθ=-35 Hence, P-2+10-35,3+1045=-8,11 and Q-2-10-35,3-1045=4,-5