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Correct option is D
We first determine the value of t corresponding to the given values of x and y. From t2+3t−8=2, we get t=2,−5, and from 2t2−2t−5=−1, we get t=2,−1. Hence to the given point there corresponds thevalue t = 2. Therefore, the slope of the tangent at (2, −1) is y'|t = 2 = dy/dtdx/dtt = 2 = 4t−22t+3t = 2 = 67Talk to our academic expert!
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The curve y= ax3+ bx2+cx + 5 touches the x-axis at P(-2, 0) and cuts the y-axis at a point Q where its gradient is 3, then the value of -10 a- 100b+ 1000 c must be
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