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The smallest positive value of general solution of $\sin θ = \frac{- 1}{2}$ is

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Correct option is B

We have sinθ=−12⇒sinθ=sin−π6⇒θ=nπ+(−1)n−π6for n=0, θ=−π6for n=1, θ=π+π6=7π6for n=2, θ=2π−π6=11π6

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The smallest positive value of general solution of sinθ=−12 is

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The smallest positive value of general solution of $\sin θ = \frac{- 1}{2}$ is