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Questions  

The smallest positive value of x (in radians) satisfying the equation logcosx32sinx=2logsecx(tanx), is

a
π12
b
π6
c
π4
d
π3

detailed solution

Correct option is B

We have logcos⁡x⁡32sin⁡x−logcos⁡x⁡(tan⁡x)=2⇒logcos⁡x⁡32cos⁡x=2⇒32cos⁡x=cos2⁡x⇒cos⁡xcos⁡x−32=0∴x=π6x=π2 is rejected

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