The solution of cos⁡y+(x siny −1)dydx=0 is xsecy = Ptany +c then ' P′ is

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answer is 1.

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Detailed Solution

dxdy+xtany=secy I.F. =e∫ tany =elog⁡sec⁡y= secy Solution of the differential equation is ysecy =∫sec2⁡ ydy = tany +c∴P=1

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