The solution of dydx=x−2y+32x−y+5 is
x2-4xy+y2+6x-10y=c
x2-4xy+y2+6x+10y=c
x2+4xy+y2+6x-10y=c
x2-4xy-y2-6x-10y=c
2xdy−ydy+5dy=xdx−2ydx+3dx→2(xdy+ydx)−ydy+5dy=xdx+3dx→∫2d(xy)−ydy+5dy=∫xdx+3dx→2xy−y22+5y=x22+3x→4xy−y2+10y=x2+6x+c→x2−4xy+y2+6x−10y=c