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Questions  

 The solution of dydx+ay=emx is (where a+m=0 ) 

a
aaxy=x+c
b
aax.y=y+c
c
aay.x=y+c
d
aay.x=x+c

detailed solution

Correct option is A

I.F=e∫a⋅dx Solution is y⋅eαx=∫e(a+m)xdx=x+c

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