The solution of the D.E [xcoty+logcosx]dy+( logsiny-ytanx )dx=0 is
sinxycosyx=C
sinyxcosxy=C
sinxxcosyy=C
tanxtany=C
[xcoty+logcosx]dy+( logsiny-ytanx )dx=0
[xcoty+logcosx]dydx +( logsiny-ytanx )=0
xcotydydx+logcosxdydx+log siny-ytanx=0
xcotydydx+logsiny-ytanx+logcosxdydx=0
∫d(xlogsiny)+∫d(ylogcosx)=C→xlogsiny+ylogcosx=C→(siny)x(cosx)y=C