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Questions  

 The solution of the DE 2x3ydy+1y2x2y2+y21dx=0 is 

a
x2y2=cx−11−y2
b
x2y2=cx+11+y2
c
xy=cx+1
d
xy=1+y2

detailed solution

Correct option is A

At Div by 1−y222y1−y22dydx+y21−y21x=1x3 Put y21−y2=u⇒2y1−y22dydx=dudx⇒dudx+ux=1x3I.F.=∫e1 1xax=x Solu. is x2y2=(cx−1)1−y2

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