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Questions  

 The solution of d.E y2x2y+exdxex+y3dy=0 is 

a
exy=y22−23x3+c
b
exy=x22−2y33+c
c
eyx=y22−23x3+c
d
eyx=y2−x3+c

detailed solution

Correct option is A

ex(ydx−dy)+2x2y2dx−y3dy=0ex(ydx−dy)y2+2x2dx−ydy=0dexy=ydy−2x2dx Integration both sides exy=y22−23x3+c

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