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Q.

The solution of d.E y2x2y+exdx−ex+y3dy=0 is

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a

exy=y22−23x3+c

b

exy=x22−2y33+c

c

eyx=y22−23x3+c

d

eyx=y2−x3+c

answer is A.

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Detailed Solution

ex(ydx−dy)+2x2y2dx−y3dy=0ex(ydx−dy)y2+2x2dx−ydy=0dexy=ydy−2x2dx Integration both sides exy=y22−23x3+c
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