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 The solution of differential equation dydx=1y2y determines family of circles with 

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a
variable radii and fixed centre at  1,0
b
variable radii and fixed centre at  0,-1
c
fixed radius 1 and variable centre along  y- axis
d
fixed radius 1 and variable centre along x- axis

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detailed solution

Correct option is D

We have, dydx=1−y2y∣ On integrating both  sides  we get ∫y1−y2dy=∫dx⇒−12∫−2y1−y2dy=∫dx⇒−1−y2=x+c On squaring both sides, we get (x+c)2+y2=1Which is the equation of circle whose fixed radius is 1 and centre is variable on x- axis


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