The solution of the differential equation d2y dx2=sin3x+ex+x2 when y1(0)=1 and y(0)=0 is
-sin3x9+ex+x412+13x-1
-sin3x9+ex+x412+13x
-cos3x9+ex+x412+13x+1
cos3x9+x412+x3-ex+1
Given that d2y dx2=sin3x+ex+x2
Integrating on both sides
dydx=−cos 3x3+ex+x33+c
And given y1(0)=1
⇒1=−13+1+0+C
⇒C=−13
∴dydx=−cos 3x3+ex+x33
Again Integrating on both sides
y=−sin3x9+ex+x412−x3+K
And given y (0) = 0
⇒0=0+1+0−0+K
∴K=−1
∴y=−sin3x9+ex+x412−x3−1