The solution of the differential equation dydx=x−2y+12x−4y is
x−2y2+2x=c
x−2y2+x=c
x−2y2+2x2=c
x−2y+x2=c
dydx=x−2y+12(x−2y) Put u=x−2y⋅dudx=1−2dydx