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Questions  

 Solution of differential equation dydx+xsin2y=sinycosy is 

a
tan⁡y=(x−1)+Ce−x
b
cot⁡y=(x−1)+Ce−x
c
tan⁡y=(x−1)ex+C
d
cot⁡y=(x−1)ex+C

detailed solution

Correct option is B

dydx+xsin2⁡y=sin⁡ycos⁡ycos⁡ec2ydydx+x=cot⁡y Let −cot⁡y=vdvdx+v=xIF =e∫1dx=exsol: vex=∫exx dx∴ −cot⁡y⋅ex=x∫exdx-∫1∫exdxdx⇒cot⁡y=(x−1)+Ce−x

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