The solution of the differential equation dydx=xy+x+y+1 is
y=12x2+x+C
log(y+1)=12x2+x+C
C(y+1)=ex2+2x2
y=12x3+x+C
dydx=xy+x+y+1
=xy+1+y+1=x+1y+1
⇒dyy+1=x+1dxIntegration on both sides⇒∫dyy+1=∫dx
logy+1=x22+x+C