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Questions  

 The solution of the differential equation f(x)dydx+f'(x)y=1 is 

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a
x=yfx+c
b
xf−1x+c=0
c
y=x+cfx
d
y=xfx

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detailed solution

Correct option is A

The given differential equation can be written as f(x)dy+f'(x)ydx=dx i.e. d(f(x)·y)=d(x) Integrating we get y·f(x)=x+c Or f(x)=x+cy

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